(9a^2)+150a+525=0

Solution for (9a^2)+150a+525=0 equation:

(9a^2)+150a+525=0

a = 9; b = 150; c = +525;
Δ = b2-4ac
Δ = 1502-4·9·525
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-60}{2*9}=\frac{-210}{18}
=-11+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+60}{2*9}=\frac{-90}{18}
=-5
$